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It required 42.35 mL of H 2 SO 4 to neutralize 21.17 mL of 0.5000 M NaOH. Calculate the concentration of H 2 SO 4. (Hint: Write a balanced reaction to help you perform the calculation.) 0.2499 M H 2 SO 4. 0.1250 M H 2 SO 4. 0.4998 M H 2 SO 4. 1.000 M H 2 SO 4. None of the above are correct.

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In general, M 1 usually refers to as the initial molarity of the solution. V 1 refers to the volume that is being transferred. M 2 refers to the final concentration of the solution and V 2 is the final total volume of the solution. Remeber that the number of moles of solute does not change when more solvent is added to the solution.

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to prepare 300 mL of 1.0 M H 2SO 4 M 1V 1 = M 2V 2 note: moles constant since (M)(V) = mol Before After (18.0 mol/L)(V 1) = (1.0 mol/L)(0.300L) V 1 = 0.0167 L V 1 = 16.7 ml So add 16.7 mL of 18.0M sulfuric acid to enough water to make 300mL solution Notice that in the above problem can use L on both sides or mL because concentration units cancel out

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Calculate the molarity of the resulting solution if 25.0 mL of 1.50 M HCl solution is diluted to 500. mL. 0.0750 M What mass of Cu(NO 3) 2 can be prepared from the reaction of 3.65 grams of copper with 5.16 grams of HNO 3?

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How many moles of KOH are contained in 750. mL of 5.00 M KOH solution? A) 6.67 mol B) 3.75 × mol C) 56.1 mol D) 3.75 mol E) none of the above

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= 0.0842 M HNO 3. The first step the unit analysis thought-process is to clearly identify the units that you want. Molarity describes the number of moles of solute per liter of solution, so we start by placing moles of HNO 3 over 1 L HNO 3 solution. Because molarity is a ratio of two units, we begin our calculation with a ratio of two units.